There are several factors which determine the rate of a specific reaction and those are expressed in the "collision theory" which states that for molecules to react, they must:

collide
have the right energy
have the right geometry

To increase the rate, you must make the above more likely to occur. This is possible by changing other factors such as:

increasing the surface area (of solids)-this allows for more collisions and gives more molecules the right geometry
increasing the temperature-this gives more molecules the right energy (also called the activation energy, E_a)
increasing the concentration (of gases and solutions)-this allows for more collisions and more correct geometry
using a catalyst-helps molecules achieve the correct geometry by providing a different way to react

The reaction rate can also be expressed by using a "rate law" and is written as follows:

For the general reaction: aA + bB + ... ----> gG + hH + .....

the reaction rate can be calculated by:

Reaction rate = k[A]^m[B]ⁿ ....

Where:

[A], [B], etc. are the concentrations of the reactants
k is the rate constant or rate coefficient, a value dependent on temperature.
m,n, etc. are exponents which correspond to a, b, etc. The concentration is raised to the power of its coefficient in the balanced equation.

Reaction order is a topic which comes with reaction rates. If you have a reaction in which A, B, and C are possible reactants, then we can describe the order of the reaction following this chart:

The order of the reaction is defined as the sum of the exponents of the coefficients. In general, first order reactions are most commonly seen, but reactions of other orders are also important. Zero-order reactions -- those for which the change in the reaction is independent of the concentration of the reaction -- are also possible.

It is possible to determine the order of a reactant, and eventually the reaction rate, using initial rate information which includes the concentration of the reactants and the rate at which the product is formed. If you double the concentration of reactant X and the rate increases by 2^a, then the order of reactant X is "a". If you triple the concentration of reactant Y and the rate increases by 3^b, then the order of Y is "b". For example, if you have a reaction with one reactant, A, and you double [A] and the rate doubles, then the rate=k[A]¹. If, instead, you double [A] and the rate quadruples, the rate=k[A]². If you double [A] and the rate stays the same, then the rate=k[A]⁰.

To find the rate constant, k, using initial rate information, just plug in one experiment's concentrations and rate into the rate law and solve. The units of k are more tricky:

units of k=units of rate/(units of concentration)^{reaction order}
Ex: for 2nd order reaction, k=(M/s)/M²=M^-1s^-1

Example Problem: Find the rate law and rate constant of A + B --> C using the following data

When dealing with reaction rates, it is sometimes important to know how to graph a straight line with the data you have. When graphing concentration versus time, there are two ways to graph a line. If you have a first order reaction, then the graph of ln[A] vs. time is a line. If you have a second order reaction, then the graph of 1/[A] vs. time produces a line.

A quantative way to examine reaction rates is through Arrhenius' Equation which states:

k=Ae^-E_a/RT

Where:

A is a constant related to the geometry needed
e is a constant, approximately 2.7281
E_a is the activation energy
R is the gas law constant, 8.314 J/mol-K
T is the temperature in kelvins

If it is a simplegeometry to attain, A will be large. If a large E_a is needed then the exponent becomes more negative and therefore decreases k. If the temperature increases then the exponent becomes less negative and therefore increases k. A pop-up calculator is available to help practice using Arrhernius' Equation to make calculations.

The following are two (2) energy profile graphs which help demonstrate energy changes during a reaction.

Not all reactions happen exactly as they are written. Most, in fact, go through an intermediate step. Reaction mechanism studies look at how a reaction actually occurs. Defined, a reaction mechanism is a series of elementary reactions that are proposed to account for the rate law (kinetics) of a particular reaction. The diagram below shows the two steps involved in a particular mechanism, and it shows how we get the reaction from the mechanism.

It is helpful to remember certain terms and facts when dealing with mechanisms. You cannot derive a mechanism from the equation and when you combine the steps of a mechanism, you end up with the reaction. The molecularity of a step tells how many molecules are involved (most involve two (2) molecules so they are bimolecular). An intermediate product is a molecule formed in one step and then used in another. One of the most important concepts to keep in mind is that the steps are not equally important. To speed up the reaction, you must speed up the slowest step (also called the rate-determining step).

rate law of slow step=rate law of reaction

When determine the rate of a step, simply make the exponent of the reactant's concentration in the rate law the same as the coefficient of the reactant in the step.

Example problem: Find the slow step of the following reaction mechanism

A catalyst is a substance added to a reaction which comes out of the reaction unchanged. As mentioned earlier, catalysts help lower the activation energy as shown in the following graph. They do this by changing the reaction mechanism.

The following is an example of how this can be done.

Practice Kinetic Quantitative Problem:

Kinetic quantitative solution.

Practice Kinetic Qualitative Problems:

Kinetic qualitative solution.

[Advanced Index] [Gas Laws] [Thermodynamics] [Kinetics] [Equilibria]
[Redox Reactions] [Nuclear Chemistry]

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